5(3a-4)=7(6a+3)-7

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Solution for 5(3a-4)=7(6a+3)-7 equation:



5(3a-4)=7(6a+3)-7
We move all terms to the left:
5(3a-4)-(7(6a+3)-7)=0
We multiply parentheses
15a-(7(6a+3)-7)-20=0
We calculate terms in parentheses: -(7(6a+3)-7), so:
7(6a+3)-7
We multiply parentheses
42a+21-7
We add all the numbers together, and all the variables
42a+14
Back to the equation:
-(42a+14)
We get rid of parentheses
15a-42a-14-20=0
We add all the numbers together, and all the variables
-27a-34=0
We move all terms containing a to the left, all other terms to the right
-27a=34
a=34/-27
a=-1+7/27

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