5(3b+1)+(16b-9)=0

Solution for 5(3b+1)+(16b-9)=0 equation:

Simplifying
5(3b + 1) + (16b + -9) = 0

Reorder the terms:
5(1 + 3b) + (16b + -9) = 0
(1 * 5 + 3b * 5) + (16b + -9) = 0
(5 + 15b) + (16b + -9) = 0

Reorder the terms:
5 + 15b + (-9 + 16b) = 0

Remove parenthesis around (-9 + 16b)
5 + 15b + -9 + 16b = 0

Reorder the terms:
5 + -9 + 15b + 16b = 0

Combine like terms: 5 + -9 = -4
-4 + 15b + 16b = 0

Combine like terms: 15b + 16b = 31b
-4 + 31b = 0

Solving
-4 + 31b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 31b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 31b = 0 + 4
31b = 0 + 4

Combine like terms: 0 + 4 = 4
31b = 4

Divide each side by '31'.
b = 0.1290322581

Simplifying
b = 0.1290322581