5(3b-2)=21+9b

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Solution for 5(3b-2)=21+9b equation: 



5(3b-2)=21+9b

We move all terms to the left:

5(3b-2)-(21+9b)=0

We add all the numbers together, and all the variables

5(3b-2)-(9b+21)=0

We multiply parentheses

15b-(9b+21)-10=0

We get rid of parentheses

15b-9b-21-10=0

We add all the numbers together, and all the variables

6b-31=0

We move all terms containing b to the left, all other terms to the right

6b=31

b=31/6

b=5+1/6

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