5(3b-4)=2(r-4)-6

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Solution for 5(3b-4)=2(r-4)-6 equation: 


Simplifying
5(3b + -4) = 2(r + -4) + -6

Reorder the terms:
5(-4 + 3b) = 2(r + -4) + -6
(-4 * 5 + 3b * 5) = 2(r + -4) + -6
(-20 + 15b) = 2(r + -4) + -6

Reorder the terms:
-20 + 15b = 2(-4 + r) + -6
-20 + 15b = (-4 * 2 + r * 2) + -6
-20 + 15b = (-8 + 2r) + -6

Reorder the terms:
-20 + 15b = -8 + -6 + 2r

Combine like terms: -8 + -6 = -14
-20 + 15b = -14 + 2r

Solving
-20 + 15b = -14 + 2r

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 15b = -14 + 20 + 2r

Combine like terms: -20 + 20 = 0
0 + 15b = -14 + 20 + 2r
15b = -14 + 20 + 2r

Combine like terms: -14 + 20 = 6
15b = 6 + 2r

Divide each side by '15'.
b = 0.4 + 0.1333333333r

Simplifying
b = 0.4 + 0.1333333333r

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