5(3c+2)+3(1-2c)=13

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Solution for 5(3c+2)+3(1-2c)=13 equation: 


Simplifying
5(3c + 2) + 3(1 + -2c) = 13

Reorder the terms:
5(2 + 3c) + 3(1 + -2c) = 13
(2 * 5 + 3c * 5) + 3(1 + -2c) = 13
(10 + 15c) + 3(1 + -2c) = 13
10 + 15c + (1 * 3 + -2c * 3) = 13
10 + 15c + (3 + -6c) = 13

Reorder the terms:
10 + 3 + 15c + -6c = 13

Combine like terms: 10 + 3 = 13
13 + 15c + -6c = 13

Combine like terms: 15c + -6c = 9c
13 + 9c = 13

Add '-13' to each side of the equation.
13 + -13 + 9c = 13 + -13

Combine like terms: 13 + -13 = 0
0 + 9c = 13 + -13
9c = 13 + -13

Combine like terms: 13 + -13 = 0
9c = 0

Solving
9c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '9'.
c = 0

Simplifying
c = 0

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