5(3c+2)+4(2c+1)=

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Solution for 5(3c+2)+4(2c+1)= equation:


Simplifying
5(3c + 2) + 4(2c + 1) = 0

Reorder the terms:
5(2 + 3c) + 4(2c + 1) = 0
(2 * 5 + 3c * 5) + 4(2c + 1) = 0
(10 + 15c) + 4(2c + 1) = 0

Reorder the terms:
10 + 15c + 4(1 + 2c) = 0
10 + 15c + (1 * 4 + 2c * 4) = 0
10 + 15c + (4 + 8c) = 0

Reorder the terms:
10 + 4 + 15c + 8c = 0

Combine like terms: 10 + 4 = 14
14 + 15c + 8c = 0

Combine like terms: 15c + 8c = 23c
14 + 23c = 0

Solving
14 + 23c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 23c = 0 + -14

Combine like terms: 14 + -14 = 0
0 + 23c = 0 + -14
23c = 0 + -14

Combine like terms: 0 + -14 = -14
23c = -14

Divide each side by '23'.
c = -0.6086956522

Simplifying
c = -0.6086956522

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