5(3c+2)+4(c-7)=20

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Solution for 5(3c+2)+4(c-7)=20 equation:


Simplifying
5(3c + 2) + 4(c + -7) = 20

Reorder the terms:
5(2 + 3c) + 4(c + -7) = 20
(2 * 5 + 3c * 5) + 4(c + -7) = 20
(10 + 15c) + 4(c + -7) = 20

Reorder the terms:
10 + 15c + 4(-7 + c) = 20
10 + 15c + (-7 * 4 + c * 4) = 20
10 + 15c + (-28 + 4c) = 20

Reorder the terms:
10 + -28 + 15c + 4c = 20

Combine like terms: 10 + -28 = -18
-18 + 15c + 4c = 20

Combine like terms: 15c + 4c = 19c
-18 + 19c = 20

Solving
-18 + 19c = 20

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 19c = 20 + 18

Combine like terms: -18 + 18 = 0
0 + 19c = 20 + 18
19c = 20 + 18

Combine like terms: 20 + 18 = 38
19c = 38

Divide each side by '19'.
c = 2

Simplifying
c = 2

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