5(3c+2)=4(5c-10)

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Solution for 5(3c+2)=4(5c-10) equation:


Simplifying
5(3c + 2) = 4(5c + -10)

Reorder the terms:
5(2 + 3c) = 4(5c + -10)
(2 * 5 + 3c * 5) = 4(5c + -10)
(10 + 15c) = 4(5c + -10)

Reorder the terms:
10 + 15c = 4(-10 + 5c)
10 + 15c = (-10 * 4 + 5c * 4)
10 + 15c = (-40 + 20c)

Solving
10 + 15c = -40 + 20c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-20c' to each side of the equation.
10 + 15c + -20c = -40 + 20c + -20c

Combine like terms: 15c + -20c = -5c
10 + -5c = -40 + 20c + -20c

Combine like terms: 20c + -20c = 0
10 + -5c = -40 + 0
10 + -5c = -40

Add '-10' to each side of the equation.
10 + -10 + -5c = -40 + -10

Combine like terms: 10 + -10 = 0
0 + -5c = -40 + -10
-5c = -40 + -10

Combine like terms: -40 + -10 = -50
-5c = -50

Divide each side by '-5'.
c = 10

Simplifying
c = 10

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