5(3c+4)+5(2b+3)=

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Solution for 5(3c+4)+5(2b+3)= equation:


Simplifying
5(3c + 4) + 5(2b + 3) = 0

Reorder the terms:
5(4 + 3c) + 5(2b + 3) = 0
(4 * 5 + 3c * 5) + 5(2b + 3) = 0
(20 + 15c) + 5(2b + 3) = 0

Reorder the terms:
20 + 15c + 5(3 + 2b) = 0
20 + 15c + (3 * 5 + 2b * 5) = 0
20 + 15c + (15 + 10b) = 0

Reorder the terms:
20 + 15 + 10b + 15c = 0

Combine like terms: 20 + 15 = 35
35 + 10b + 15c = 0

Solving
35 + 10b + 15c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-35' to each side of the equation.
35 + 10b + -35 + 15c = 0 + -35

Reorder the terms:
35 + -35 + 10b + 15c = 0 + -35

Combine like terms: 35 + -35 = 0
0 + 10b + 15c = 0 + -35
10b + 15c = 0 + -35

Combine like terms: 0 + -35 = -35
10b + 15c = -35

Add '-15c' to each side of the equation.
10b + 15c + -15c = -35 + -15c

Combine like terms: 15c + -15c = 0
10b + 0 = -35 + -15c
10b = -35 + -15c

Divide each side by '10'.
b = -3.5 + -1.5c

Simplifying
b = -3.5 + -1.5c

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