5(3c+6)=4(2c+11)

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Solution for 5(3c+6)=4(2c+11) equation: 



5(3c+6)=4(2c+11)

We move all terms to the left:

5(3c+6)-(4(2c+11))=0

We multiply parentheses

15c-(4(2c+11))+30=0



We calculate terms in parentheses: -(4(2c+11)), so:

4(2c+11)

We multiply parentheses

8c+44

Back to the equation:

-(8c+44)



We get rid of parentheses

15c-8c-44+30=0

We add all the numbers together, and all the variables

7c-14=0

We move all terms containing c to the left, all other terms to the right

7c=14

c=14/7

c=2

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