5(3c-12)+6=6

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Solution for 5(3c-12)+6=6 equation: 



5(3c-12)+6=6

We move all terms to the left:

5(3c-12)+6-(6)=0

We add all the numbers together, and all the variables

5(3c-12)=0

We multiply parentheses

15c-60=0

We move all terms containing c to the left, all other terms to the right

15c=60

c=60/15

c=4

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