5(3c-2)+1=-(c+4)

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Solution for 5(3c-2)+1=-(c+4) equation: 



5(3c-2)+1=-(c+4)

We move all terms to the left:

5(3c-2)+1-(-(c+4))=0

We multiply parentheses

15c-(-(c+4))-10+1=0



We calculate terms in parentheses: -(-(c+4)), so:

-(c+4)

We get rid of parentheses

-c-4

We add all the numbers together, and all the variables

-1c-4

Back to the equation:

-(-1c-4)



We add all the numbers together, and all the variables

15c-(-1c-4)-9=0

We get rid of parentheses

15c+1c+4-9=0

We add all the numbers together, and all the variables

16c-5=0

We move all terms containing c to the left, all other terms to the right

16c=5

c=5/16

c=5/16

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