5(3c-2)+c=42

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Solution for 5(3c-2)+c=42 equation: 



5(3c-2)+c=42

We move all terms to the left:

5(3c-2)+c-(42)=0

We add all the numbers together, and all the variables

c+5(3c-2)-42=0

We multiply parentheses

c+15c-10-42=0

We add all the numbers together, and all the variables

16c-52=0

We move all terms containing c to the left, all other terms to the right

16c=52

c=52/16

c=3+1/4

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