5(3c-2)-4c+12=68

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Solution for 5(3c-2)-4c+12=68 equation:


Simplifying
5(3c + -2) + -4c + 12 = 68

Reorder the terms:
5(-2 + 3c) + -4c + 12 = 68
(-2 * 5 + 3c * 5) + -4c + 12 = 68
(-10 + 15c) + -4c + 12 = 68

Reorder the terms:
-10 + 12 + 15c + -4c = 68

Combine like terms: -10 + 12 = 2
2 + 15c + -4c = 68

Combine like terms: 15c + -4c = 11c
2 + 11c = 68

Solving
2 + 11c = 68

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 11c = 68 + -2

Combine like terms: 2 + -2 = 0
0 + 11c = 68 + -2
11c = 68 + -2

Combine like terms: 68 + -2 = 66
11c = 66

Divide each side by '11'.
c = 6

Simplifying
c = 6

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