5(3c-2)-7c=40-2c(3)

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Solution for 5(3c-2)-7c=40-2c(3) equation: 



5(3c-2)-7c=40-2c(3)

We move all terms to the left:

5(3c-2)-7c-(40-2c(3))=0

We add all the numbers together, and all the variables

-(-2c^3+40)+5(3c-2)-7c=0

We add all the numbers together, and all the variables

-(-2c^3+40)-7c+5(3c-2)=0

We multiply parentheses

-(-2c^3+40)-7c+15c-10=0

We get rid of parentheses

2c^3-7c+15c-40-10=0

We do not support ecpression: c^3

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