5(3c-2)-7c=40-2cc=

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Solution for 5(3c-2)-7c=40-2cc= equation:



5(3c-2)-7c=40-2cc=
We move all terms to the left:
5(3c-2)-7c-(40-2cc)=0
We add all the numbers together, and all the variables
5(3c-2)-7c-(-2cc+40)=0
We add all the numbers together, and all the variables
-7c+5(3c-2)-(-2cc+40)=0
We multiply parentheses
-7c+15c-(-2cc+40)-10=0
We get rid of parentheses
-7c+15c+2cc-40-10=0
We add all the numbers together, and all the variables
8c+2cc-50=0
We move all terms containing c to the left, all other terms to the right
8c+2cc=50

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