5(3c-2)=40-2c

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Solution for 5(3c-2)=40-2c equation:


Simplifying
5(3c + -2) = 40 + -2c

Reorder the terms:
5(-2 + 3c) = 40 + -2c
(-2 * 5 + 3c * 5) = 40 + -2c
(-10 + 15c) = 40 + -2c

Solving
-10 + 15c = 40 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
-10 + 15c + 2c = 40 + -2c + 2c

Combine like terms: 15c + 2c = 17c
-10 + 17c = 40 + -2c + 2c

Combine like terms: -2c + 2c = 0
-10 + 17c = 40 + 0
-10 + 17c = 40

Add '10' to each side of the equation.
-10 + 10 + 17c = 40 + 10

Combine like terms: -10 + 10 = 0
0 + 17c = 40 + 10
17c = 40 + 10

Combine like terms: 40 + 10 = 50
17c = 50

Divide each side by '17'.
c = 2.941176471

Simplifying
c = 2.941176471

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