5(3d+2)+15=4(2d+5)+7d+5

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Solution for 5(3d+2)+15=4(2d+5)+7d+5 equation:


Simplifying
5(3d + 2) + 15 = 4(2d + 5) + 7d + 5

Reorder the terms:
5(2 + 3d) + 15 = 4(2d + 5) + 7d + 5
(2 * 5 + 3d * 5) + 15 = 4(2d + 5) + 7d + 5
(10 + 15d) + 15 = 4(2d + 5) + 7d + 5

Reorder the terms:
10 + 15 + 15d = 4(2d + 5) + 7d + 5

Combine like terms: 10 + 15 = 25
25 + 15d = 4(2d + 5) + 7d + 5

Reorder the terms:
25 + 15d = 4(5 + 2d) + 7d + 5
25 + 15d = (5 * 4 + 2d * 4) + 7d + 5
25 + 15d = (20 + 8d) + 7d + 5

Reorder the terms:
25 + 15d = 20 + 5 + 8d + 7d

Combine like terms: 20 + 5 = 25
25 + 15d = 25 + 8d + 7d

Combine like terms: 8d + 7d = 15d
25 + 15d = 25 + 15d

Add '-25' to each side of the equation.
25 + -25 + 15d = 25 + -25 + 15d

Combine like terms: 25 + -25 = 0
0 + 15d = 25 + -25 + 15d
15d = 25 + -25 + 15d

Combine like terms: 25 + -25 = 0
15d = 0 + 15d
15d = 15d

Add '-15d' to each side of the equation.
15d + -15d = 15d + -15d

Combine like terms: 15d + -15d = 0
0 = 15d + -15d

Combine like terms: 15d + -15d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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