5(3d-2)=2(2d+5)

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Solution for 5(3d-2)=2(2d+5) equation: 



5(3d-2)=2(2d+5)

We move all terms to the left:

5(3d-2)-(2(2d+5))=0

We multiply parentheses

15d-(2(2d+5))-10=0



We calculate terms in parentheses: -(2(2d+5)), so:

2(2d+5)

We multiply parentheses

4d+10

Back to the equation:

-(4d+10)



We get rid of parentheses

15d-4d-10-10=0

We add all the numbers together, and all the variables

11d-20=0

We move all terms containing d to the left, all other terms to the right

11d=20

d=20/11

d=1+9/11

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