5(3e+1)=35

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Solution for 5(3e+1)=35 equation: 



5(3e+1)=35

We move all terms to the left:

5(3e+1)-(35)=0

We multiply parentheses

15e+5-35=0

We add all the numbers together, and all the variables

15e-30=0

We move all terms containing e to the left, all other terms to the right

15e=30

e=30/15

e=2

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