5(3j+1)-10j=-(2-7j)

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Solution for 5(3j+1)-10j=-(2-7j) equation:



5(3j+1)-10j=-(2-7j)
We move all terms to the left:
5(3j+1)-10j-(-(2-7j))=0
We add all the numbers together, and all the variables
5(3j+1)-10j-(-(-7j+2))=0
We add all the numbers together, and all the variables
-10j+5(3j+1)-(-(-7j+2))=0
We multiply parentheses
-10j+15j-(-(-7j+2))+5=0
We calculate terms in parentheses: -(-(-7j+2)), so:
-(-7j+2)
We get rid of parentheses
7j-2
Back to the equation:
-(7j-2)
We add all the numbers together, and all the variables
5j-(7j-2)+5=0
We get rid of parentheses
5j-7j+2+5=0
We add all the numbers together, and all the variables
-2j+7=0
We move all terms containing j to the left, all other terms to the right
-2j=-7
j=-7/-2
j=3+1/2

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