5(3n+3)=7(7n+2)+7

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Solution for 5(3n+3)=7(7n+2)+7 equation: 



5(3n+3)=7(7n+2)+7

We move all terms to the left:

5(3n+3)-(7(7n+2)+7)=0

We multiply parentheses

15n-(7(7n+2)+7)+15=0



We calculate terms in parentheses: -(7(7n+2)+7), so:

7(7n+2)+7

We multiply parentheses

49n+14+7

We add all the numbers together, and all the variables

49n+21

Back to the equation:

-(49n+21)



We get rid of parentheses

15n-49n-21+15=0

We add all the numbers together, and all the variables

-34n-6=0

We move all terms containing n to the left, all other terms to the right

-34n=6

n=6/-34

n=-3/17

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