5(3n-2)=2(n+3)-3

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Solution for 5(3n-2)=2(n+3)-3 equation:



5(3n-2)=2(n+3)-3
We move all terms to the left:
5(3n-2)-(2(n+3)-3)=0
We multiply parentheses
15n-(2(n+3)-3)-10=0
We calculate terms in parentheses: -(2(n+3)-3), so:
2(n+3)-3
We multiply parentheses
2n+6-3
We add all the numbers together, and all the variables
2n+3
Back to the equation:
-(2n+3)
We get rid of parentheses
15n-2n-3-10=0
We add all the numbers together, and all the variables
13n-13=0
We move all terms containing n to the left, all other terms to the right
13n=13
n=13/13
n=1

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