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5(3n-7)-3n=1+6(1+n)
We move all terms to the left:
5(3n-7)-3n-(1+6(1+n))=0
We add all the numbers together, and all the variables
5(3n-7)-3n-(1+6(n+1))=0
We add all the numbers together, and all the variables
-3n+5(3n-7)-(1+6(n+1))=0
We multiply parentheses
-3n+15n-(1+6(n+1))-35=0
We calculate terms in parentheses: -(1+6(n+1)), so:We add all the numbers together, and all the variables
1+6(n+1)
determiningTheFunctionDomain 6(n+1)+1
We multiply parentheses
6n+6+1
We add all the numbers together, and all the variables
6n+7
Back to the equation:
-(6n+7)
12n-(6n+7)-35=0
We get rid of parentheses
12n-6n-7-35=0
We add all the numbers together, and all the variables
6n-42=0
We move all terms containing n to the left, all other terms to the right
6n=42
n=42/6
n=7
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