5(3p-2)=26-6(2p+3)=

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Solution for 5(3p-2)=26-6(2p+3)= equation: 



5(3p-2)=26-6(2p+3)=

We move all terms to the left:

5(3p-2)-(26-6(2p+3))=0

We multiply parentheses

15p-(26-6(2p+3))-10=0



We calculate terms in parentheses: -(26-6(2p+3)), so:

26-6(2p+3)

determiningTheFunctionDomain
-6(2p+3)+26

We multiply parentheses

-12p-18+26

We add all the numbers together, and all the variables

-12p+8

Back to the equation:

-(-12p+8)



We get rid of parentheses

15p+12p-8-10=0

We add all the numbers together, and all the variables

27p-18=0

We move all terms containing p to the left, all other terms to the right

27p=18

p=18/27

p=2/3

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