5(3r+7)+r=3(r-3)

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Solution for 5(3r+7)+r=3(r-3) equation: 



5(3r+7)+r=3(r-3)

We move all terms to the left:

5(3r+7)+r-(3(r-3))=0

We add all the numbers together, and all the variables

r+5(3r+7)-(3(r-3))=0

We multiply parentheses

r+15r-(3(r-3))+35=0



We calculate terms in parentheses: -(3(r-3)), so:

3(r-3)

We multiply parentheses

3r-9

Back to the equation:

-(3r-9)



We add all the numbers together, and all the variables

16r-(3r-9)+35=0

We get rid of parentheses

16r-3r+9+35=0

We add all the numbers together, and all the variables

13r+44=0

We move all terms containing r to the left, all other terms to the right

13r=-44

r=-44/13

r=-3+5/13

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