5(3r-7)=16+(4-5r)

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Solution for 5(3r-7)=16+(4-5r) equation: 



5(3r-7)=16+(4-5r)

We move all terms to the left:

5(3r-7)-(16+(4-5r))=0

We add all the numbers together, and all the variables

5(3r-7)-(16+(-5r+4))=0

We multiply parentheses

15r-(16+(-5r+4))-35=0



We calculate terms in parentheses: -(16+(-5r+4)), so:

16+(-5r+4)

determiningTheFunctionDomain
(-5r+4)+16

We get rid of parentheses

-5r+4+16

We add all the numbers together, and all the variables

-5r+20

Back to the equation:

-(-5r+20)



We get rid of parentheses

15r+5r-20-35=0

We add all the numbers together, and all the variables

20r-55=0

We move all terms containing r to the left, all other terms to the right

20r=55

r=55/20

r=2+3/4

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