5(3t+1)-13=t-(t-7)

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Solution for 5(3t+1)-13=t-(t-7) equation: 



5(3t+1)-13=t-(t-7)

We move all terms to the left:

5(3t+1)-13-(t-(t-7))=0

We multiply parentheses

15t-(t-(t-7))+5-13=0



We calculate terms in parentheses: -(t-(t-7)), so:

t-(t-7)

We get rid of parentheses

t-t+7

We add all the numbers together, and all the variables

7

Back to the equation:

-(7)



We add all the numbers together, and all the variables

15t-15=0

We move all terms containing t to the left, all other terms to the right

15t=15

t=15/15

t=1

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