5(3t-2)=-3(7+t)

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Solution for 5(3t-2)=-3(7+t) equation: 



5(3t-2)=-3(7+t)

We move all terms to the left:

5(3t-2)-(-3(7+t))=0

We add all the numbers together, and all the variables

5(3t-2)-(-3(t+7))=0

We multiply parentheses

15t-(-3(t+7))-10=0



We calculate terms in parentheses: -(-3(t+7)), so:

-3(t+7)

We multiply parentheses

-3t-21

Back to the equation:

-(-3t-21)



We get rid of parentheses

15t+3t+21-10=0

We add all the numbers together, and all the variables

18t+11=0

We move all terms containing t to the left, all other terms to the right

18t=-11

t=-11/18

t=-11/18

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