5(3v+3)+8v+5=6(v-3)-2v

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Solution for 5(3v+3)+8v+5=6(v-3)-2v equation: 



5(3v+3)+8v+5=6(v-3)-2v

We move all terms to the left:

5(3v+3)+8v+5-(6(v-3)-2v)=0

We add all the numbers together, and all the variables

8v+5(3v+3)-(6(v-3)-2v)+5=0

We multiply parentheses

8v+15v-(6(v-3)-2v)+15+5=0



We calculate terms in parentheses: -(6(v-3)-2v), so:

6(v-3)-2v

We add all the numbers together, and all the variables

-2v+6(v-3)

We multiply parentheses

-2v+6v-18

We add all the numbers together, and all the variables

4v-18

Back to the equation:

-(4v-18)



We add all the numbers together, and all the variables

23v-(4v-18)+20=0

We get rid of parentheses

23v-4v+18+20=0

We add all the numbers together, and all the variables

19v+38=0

We move all terms containing v to the left, all other terms to the right

19v=-38

v=-38/19

v=-2

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