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5(3w-5)-4=4-5(5w-3)
We move all terms to the left:
5(3w-5)-4-(4-5(5w-3))=0
We multiply parentheses
15w-(4-5(5w-3))-25-4=0
We calculate terms in parentheses: -(4-5(5w-3)), so:We add all the numbers together, and all the variables
4-5(5w-3)
determiningTheFunctionDomain -5(5w-3)+4
We multiply parentheses
-25w+15+4
We add all the numbers together, and all the variables
-25w+19
Back to the equation:
-(-25w+19)
15w-(-25w+19)-29=0
We get rid of parentheses
15w+25w-19-29=0
We add all the numbers together, and all the variables
40w-48=0
We move all terms containing w to the left, all other terms to the right
40w=48
w=48/40
w=1+1/5
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