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5(3x+1)-2x=2(x-2)
We move all terms to the left:
5(3x+1)-2x-(2(x-2))=0
We add all the numbers together, and all the variables
-2x+5(3x+1)-(2(x-2))=0
We multiply parentheses
-2x+15x-(2(x-2))+5=0
We calculate terms in parentheses: -(2(x-2)), so:We add all the numbers together, and all the variables
2(x-2)
We multiply parentheses
2x-4
Back to the equation:
-(2x-4)
13x-(2x-4)+5=0
We get rid of parentheses
13x-2x+4+5=0
We add all the numbers together, and all the variables
11x+9=0
We move all terms containing x to the left, all other terms to the right
11x=-9
x=-9/11
x=-9/11
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