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5(3x+1)=15(x-1)+20
We move all terms to the left:
5(3x+1)-(15(x-1)+20)=0
We multiply parentheses
15x-(15(x-1)+20)+5=0
We calculate terms in parentheses: -(15(x-1)+20), so:We get rid of parentheses
15(x-1)+20
We multiply parentheses
15x-15+20
We add all the numbers together, and all the variables
15x+5
Back to the equation:
-(15x+5)
15x-15x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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