5(3x+1)=2(x-2)

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Solution for 5(3x+1)=2(x-2) equation: 



5(3x+1)=2(x-2)

We move all terms to the left:

5(3x+1)-(2(x-2))=0

We multiply parentheses

15x-(2(x-2))+5=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

15x-2x+4+5=0

We add all the numbers together, and all the variables

13x+9=0

We move all terms containing x to the left, all other terms to the right

13x=-9

x=-9/13

x=-9/13

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