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5(3x+2)-2x(2+x)=0
We add all the numbers together, and all the variables
5(3x+2)-2x(x+2)=0
We multiply parentheses
-2x^2+15x-4x+10=0
We add all the numbers together, and all the variables
-2x^2+11x+10=0
a = -2; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·(-2)·10
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{201}}{2*-2}=\frac{-11-\sqrt{201}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{201}}{2*-2}=\frac{-11+\sqrt{201}}{-4} $
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