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5(3x+2)=-3(2x-4)
We move all terms to the left:
5(3x+2)-(-3(2x-4))=0
We multiply parentheses
15x-(-3(2x-4))+10=0
We calculate terms in parentheses: -(-3(2x-4)), so:We get rid of parentheses
-3(2x-4)
We multiply parentheses
-6x+12
Back to the equation:
-(-6x+12)
15x+6x-12+10=0
We add all the numbers together, and all the variables
21x-2=0
We move all terms containing x to the left, all other terms to the right
21x=2
x=2/21
x=2/21
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