5(3x+2)=x+9x+2(x-3)

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Solution for 5(3x+2)=x+9x+2(x-3) equation: 



5(3x+2)=x+9x+2(x-3)

We move all terms to the left:

5(3x+2)-(x+9x+2(x-3))=0

We multiply parentheses

15x-(x+9x+2(x-3))+10=0



We calculate terms in parentheses: -(x+9x+2(x-3)), so:

x+9x+2(x-3)

We add all the numbers together, and all the variables

10x+2(x-3)

We multiply parentheses

10x+2x-6

We add all the numbers together, and all the variables

12x-6

Back to the equation:

-(12x-6)



We get rid of parentheses

15x-12x+6+10=0

We add all the numbers together, and all the variables

3x+16=0

We move all terms containing x to the left, all other terms to the right

3x=-16

x=-16/3

x=-5+1/3

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