5(3x+4)+2x=7-3(-2x+11)

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Solution for 5(3x+4)+2x=7-3(-2x+11) equation: 



5(3x+4)+2x=7-3(-2x+11)

We move all terms to the left:

5(3x+4)+2x-(7-3(-2x+11))=0

We add all the numbers together, and all the variables

2x+5(3x+4)-(7-3(-2x+11))=0

We multiply parentheses

2x+15x-(7-3(-2x+11))+20=0



We calculate terms in parentheses: -(7-3(-2x+11)), so:

7-3(-2x+11)

determiningTheFunctionDomain
-3(-2x+11)+7

We multiply parentheses

6x-33+7

We add all the numbers together, and all the variables

6x-26

Back to the equation:

-(6x-26)



We add all the numbers together, and all the variables

17x-(6x-26)+20=0

We get rid of parentheses

17x-6x+26+20=0

We add all the numbers together, and all the variables

11x+46=0

We move all terms containing x to the left, all other terms to the right

11x=-46

x=-46/11

x=-4+2/11

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