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5(3x+4)-2x=7x-2(-2x+11)
We move all terms to the left:
5(3x+4)-2x-(7x-2(-2x+11))=0
We add all the numbers together, and all the variables
-2x+5(3x+4)-(7x-2(-2x+11))=0
We multiply parentheses
-2x+15x-(7x-2(-2x+11))+20=0
We calculate terms in parentheses: -(7x-2(-2x+11)), so:We add all the numbers together, and all the variables
7x-2(-2x+11)
We multiply parentheses
7x+4x-22
We add all the numbers together, and all the variables
11x-22
Back to the equation:
-(11x-22)
13x-(11x-22)+20=0
We get rid of parentheses
13x-11x+22+20=0
We add all the numbers together, and all the variables
2x+42=0
We move all terms containing x to the left, all other terms to the right
2x=-42
x=-42/2
x=-21
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