5(3x+4)=11+3(4x+9)

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Solution for 5(3x+4)=11+3(4x+9) equation: 



5(3x+4)=11+3(4x+9)

We move all terms to the left:

5(3x+4)-(11+3(4x+9))=0

We multiply parentheses

15x-(11+3(4x+9))+20=0



We calculate terms in parentheses: -(11+3(4x+9)), so:

11+3(4x+9)

determiningTheFunctionDomain
3(4x+9)+11

We multiply parentheses

12x+27+11

We add all the numbers together, and all the variables

12x+38

Back to the equation:

-(12x+38)



We get rid of parentheses

15x-12x-38+20=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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