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5(3x+4)=4(x-5)+14
We move all terms to the left:
5(3x+4)-(4(x-5)+14)=0
We multiply parentheses
15x-(4(x-5)+14)+20=0
We calculate terms in parentheses: -(4(x-5)+14), so:We get rid of parentheses
4(x-5)+14
We multiply parentheses
4x-20+14
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
15x-4x+6+20=0
We add all the numbers together, and all the variables
11x+26=0
We move all terms containing x to the left, all other terms to the right
11x=-26
x=-26/11
x=-2+4/11
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