5(3x+5)+(2+1)=6(x+2)+3(x+10)

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Solution for 5(3x+5)+(2+1)=6(x+2)+3(x+10) equation: 



5(3x+5)+(2+1)=6(x+2)+3(x+10)

We move all terms to the left:

5(3x+5)+(2+1)-(6(x+2)+3(x+10))=0

We add all the numbers together, and all the variables

5(3x+5)-(6(x+2)+3(x+10))+3=0

We multiply parentheses

15x-(6(x+2)+3(x+10))+25+3=0



We calculate terms in parentheses: -(6(x+2)+3(x+10)), so:

6(x+2)+3(x+10)

We multiply parentheses

6x+3x+12+30

We add all the numbers together, and all the variables

9x+42

Back to the equation:

-(9x+42)



We add all the numbers together, and all the variables

15x-(9x+42)+28=0

We get rid of parentheses

15x-9x-42+28=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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