5(3x+6x-10)=5(2x+40)

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Solution for 5(3x+6x-10)=5(2x+40) equation:



5(3x+6x-10)=5(2x+40)
We move all terms to the left:
5(3x+6x-10)-(5(2x+40))=0
We add all the numbers together, and all the variables
5(9x-10)-(5(2x+40))=0
We multiply parentheses
45x-(5(2x+40))-50=0
We calculate terms in parentheses: -(5(2x+40)), so:
5(2x+40)
We multiply parentheses
10x+200
Back to the equation:
-(10x+200)
We get rid of parentheses
45x-10x-200-50=0
We add all the numbers together, and all the variables
35x-250=0
We move all terms containing x to the left, all other terms to the right
35x=250
x=250/35
x=7+1/7

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