5(3x+7)+4(7x-2)=65

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Solution for 5(3x+7)+4(7x-2)=65 equation: 



5(3x+7)+4(7x-2)=65

We move all terms to the left:

5(3x+7)+4(7x-2)-(65)=0

We multiply parentheses

15x+28x+35-8-65=0

We add all the numbers together, and all the variables

43x-38=0

We move all terms containing x to the left, all other terms to the right

43x=38

x=38/43

x=38/43

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