5(3x+7)=20+(x+1)

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Solution for 5(3x+7)=20+(x+1) equation:



5(3x+7)=20+(x+1)
We move all terms to the left:
5(3x+7)-(20+(x+1))=0
We multiply parentheses
15x-(20+(x+1))+35=0
We calculate terms in parentheses: -(20+(x+1)), so:
20+(x+1)
determiningTheFunctionDomain (x+1)+20
We get rid of parentheses
x+1+20
We add all the numbers together, and all the variables
x+21
Back to the equation:
-(x+21)
We get rid of parentheses
15x-x-21+35=0
We add all the numbers together, and all the variables
14x+14=0
We move all terms containing x to the left, all other terms to the right
14x=-14
x=-14/14
x=-1

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