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5(3x+7)=3(2x-5)
We move all terms to the left:
5(3x+7)-(3(2x-5))=0
We multiply parentheses
15x-(3(2x-5))+35=0
We calculate terms in parentheses: -(3(2x-5)), so:We get rid of parentheses
3(2x-5)
We multiply parentheses
6x-15
Back to the equation:
-(6x-15)
15x-6x+15+35=0
We add all the numbers together, and all the variables
9x+50=0
We move all terms containing x to the left, all other terms to the right
9x=-50
x=-50/9
x=-5+5/9
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