5(3x-1)+2(x-3)=3(x-7)+10

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Solution for 5(3x-1)+2(x-3)=3(x-7)+10 equation: 



5(3x-1)+2(x-3)=3(x-7)+10

We move all terms to the left:

5(3x-1)+2(x-3)-(3(x-7)+10)=0

We multiply parentheses

15x+2x-(3(x-7)+10)-5-6=0



We calculate terms in parentheses: -(3(x-7)+10), so:

3(x-7)+10

We multiply parentheses

3x-21+10

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)



We add all the numbers together, and all the variables

17x-(3x-11)-11=0

We get rid of parentheses

17x-3x+11-11=0

We add all the numbers together, and all the variables

14x=0

x=0/14

x=0

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