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5(3x-1)-2(7x+1)=3(2x+5)-(x+1)
We move all terms to the left:
5(3x-1)-2(7x+1)-(3(2x+5)-(x+1))=0
We multiply parentheses
15x-14x-(3(2x+5)-(x+1))-5-2=0
We calculate terms in parentheses: -(3(2x+5)-(x+1)), so:We add all the numbers together, and all the variables
3(2x+5)-(x+1)
We multiply parentheses
6x-(x+1)+15
We get rid of parentheses
6x-x-1+15
We add all the numbers together, and all the variables
5x+14
Back to the equation:
-(5x+14)
x-(5x+14)-7=0
We get rid of parentheses
x-5x-14-7=0
We add all the numbers together, and all the variables
-4x-21=0
We move all terms containing x to the left, all other terms to the right
-4x=21
x=21/-4
x=-5+1/4
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