5(3x-1)-4(2x-19)=3(2x+5)-2

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Solution for 5(3x-1)-4(2x-19)=3(2x+5)-2 equation: 



5(3x-1)-4(2x-19)=3(2x+5)-2

We move all terms to the left:

5(3x-1)-4(2x-19)-(3(2x+5)-2)=0

We multiply parentheses

15x-8x-(3(2x+5)-2)-5+76=0



We calculate terms in parentheses: -(3(2x+5)-2), so:

3(2x+5)-2

We multiply parentheses

6x+15-2

We add all the numbers together, and all the variables

6x+13

Back to the equation:

-(6x+13)



We add all the numbers together, and all the variables

7x-(6x+13)+71=0

We get rid of parentheses

7x-6x-13+71=0

We add all the numbers together, and all the variables

x+58=0

We move all terms containing x to the left, all other terms to the right

x=-58

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