5(3x-19)=2(x-37)-35

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Solution for 5(3x-19)=2(x-37)-35 equation: 



5(3x-19)=2(x-37)-35

We move all terms to the left:

5(3x-19)-(2(x-37)-35)=0

We multiply parentheses

15x-(2(x-37)-35)-95=0



We calculate terms in parentheses: -(2(x-37)-35), so:

2(x-37)-35

We multiply parentheses

2x-74-35

We add all the numbers together, and all the variables

2x-109

Back to the equation:

-(2x-109)



We get rid of parentheses

15x-2x+109-95=0

We add all the numbers together, and all the variables

13x+14=0

We move all terms containing x to the left, all other terms to the right

13x=-14

x=-14/13

x=-1+1/13

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